Polygon Interior and Exterior Angle Sums
Polygon Interior and Exterior Angle Sums
Polygons are closed shapes made from straight line segments. Examples include triangles, quadrilaterals, pentagons, hexagons, and many more.
In this lesson, you will learn two very important facts about polygons:
- How to find the sum of the interior angles of any polygon.
- Why the sum of one exterior angle at each vertex is always \(360^\circ\).
These ideas help you solve many geometry problems, especially when some angles are missing.
1. Interior angles of a polygon
An interior angle is an angle inside a polygon, formed by two sides meeting at a vertex.
For example:
- A triangle has 3 interior angles.
- A quadrilateral has 4 interior angles.
- A pentagon has 5 interior angles.
2. Finding the sum of interior angles
There is a general formula for the sum of the interior angles of an \(n\)-sided polygon:
$$ \text{Interior angle sum} = (n-2)\times 180^\circ $$Here, \(n\) is the number of sides.
Why does this formula work?
You can divide a polygon into triangles by drawing diagonals from one vertex to all other non-adjacent vertices.
This creates exactly \(n-2\) triangles.
Since each triangle has an angle sum of \(180^\circ\), the total interior angle sum is:
$$ (n-2)\times 180^\circ $$Examples of the formula
- Triangle: \((3-2)\times 180 = 180^\circ\)
- Quadrilateral: \((4-2)\times 180 = 360^\circ\)
- Pentagon: \((5-2)\times 180 = 540^\circ\)
- Hexagon: \((6-2)\times 180 = 720^\circ\)
3. Exterior angles of a polygon
An exterior angle is formed when one side of a polygon is extended. It is outside the polygon.
At each vertex, the interior angle and its exterior angle form a straight line, so they add up to \(180^\circ\).
$$ \text{interior angle} + \text{exterior angle} = 180^\circ $$4. Sum of exterior angles
If you take one exterior angle at each vertex of any polygon, always going around the shape in the same direction, the sum is always:
$$ 360^\circ $$Why is the exterior angle sum always \(360^\circ\)?
Imagine walking around the outside of a polygon. At each corner, you turn by the exterior angle. After going all the way around and returning to where you started, you have made one full turn.
One full turn is:
$$ 360^\circ $$So the sum of the exterior angles of any polygon is always \(360^\circ\).
5. Connecting interior and exterior angle sums
Suppose a polygon has \(n\) sides.
There are \(n\) interior angles and \(n\) exterior angles, and each interior-exterior pair adds to \(180^\circ\). So:
$$ \text{sum of all interior and exterior pairs} = n\times 180^\circ $$Since the exterior sum is \(360^\circ\), we can write:
$$ \text{interior sum} + 360^\circ = n\times 180^\circ $$Now subtract \(360^\circ\):
$$ \text{interior sum} = n\times 180^\circ - 360^\circ $$ $$ \text{interior sum} = (n-2)\times 180^\circ $$This matches the formula from dividing the polygon into triangles.
6. Regular polygons
A regular polygon has all sides equal and all angles equal.
In a regular polygon:
- All interior angles are the same.
- All exterior angles are the same.
Since the exterior angles always add to \(360^\circ\), each exterior angle in a regular \(n\)-gon is:
$$ \frac{360^\circ}{n} $$Then each interior angle is:
$$ 180^\circ - \frac{360^\circ}{n} $$You can also find each interior angle of a regular polygon by dividing the interior sum by the number of angles:
$$ \frac{(n-2)\times 180^\circ}{n} $$These two methods give the same answer.
Worked Example 1: Find the sum of the interior angles of an octagon
An octagon has \(8\) sides, so \(n=8\).
$$ \text{Interior angle sum} = (8-2)\times 180^\circ $$ $$ = 6\times 180^\circ = 1080^\circ $$Answer: The sum of the interior angles is \(1080^\circ\).
Worked Example 2: Find one exterior angle of a regular nonagon
A nonagon has \(9\) sides.
For a regular polygon, each exterior angle is:
$$ \frac{360^\circ}{n} = \frac{360^\circ}{9} = 40^\circ $$Answer: Each exterior angle is \(40^\circ\).
Worked Example 3: Find one interior angle of a regular hexagon
A regular hexagon has \(6\) equal exterior angles.
First find one exterior angle:
$$ \frac{360^\circ}{6} = 60^\circ $$Now use the fact that an interior angle and exterior angle form a straight line:
$$ \text{interior angle} = 180^\circ - 60^\circ = 120^\circ $$Answer: Each interior angle is \(120^\circ\).
Worked Example 4: One interior angle of a regular polygon is \(150^\circ\). How many sides does the polygon have?
First find the exterior angle:
$$ 180^\circ - 150^\circ = 30^\circ $$Now use the exterior angle formula for a regular polygon:
$$ \frac{360^\circ}{n} = 30^\circ $$Solve for \(n\):
$$ n = \frac{360}{30} = 12 $$Answer: The polygon has \(12\) sides.
7. Common mistakes to avoid
- Mixing up interior and exterior angles: interior angles are inside the polygon; exterior angles are outside.
- Using \((n-2)\times 180\) for one angle: this formula gives the sum of all interior angles, not just one angle.
- Forgetting that exterior angles sum to \(360^\circ\): this is true for any polygon if you choose one exterior angle at each vertex consistently.
- Assuming all polygons are regular: you can only divide by \(n\) to get one angle when the polygon is regular.
8. Quick problem-solving steps
If you need the sum of interior angles:
- Count the number of sides, \(n\).
- Use $$ (n-2)\times 180^\circ $$
If you need one exterior angle of a regular polygon:
- Count the sides, \(n\).
- Use $$ \frac{360^\circ}{n} $$
If you need one interior angle of a regular polygon:
- Find the exterior angle using $$ \frac{360^\circ}{n} $$
- Subtract from \(180^\circ\)
9. Lesson summary
The sum of the interior angles of an \(n\)-sided polygon is:
$$ (n-2)\times 180^\circ $$This works because any polygon can be split into \(n-2\) triangles.
The sum of one exterior angle at each vertex of any polygon is always:
$$ 360^\circ $$For a regular polygon, each exterior angle is \(\frac{360^\circ}{n}\), and each interior angle is \(180^\circ - \frac{360^\circ}{n}\).
Once you understand these rules, you can solve many angle problems involving polygons quickly and confidently.
Put what you read to the test
You've worked through Polygon Interior and Exterior Angle Sums. Try answering a few questions to see what stuck — and what might deserve a quick reread before you move on.