Arithmetic Sequences
Arithmetic Sequences are patterns of numbers where the same amount is added or subtracted each time.
They are important because they model steady, linear growth. For example, if you save the same number of dollars every week, or if a stairway goes up by the same height each step, the pattern can often be described by an arithmetic sequence.
In this lesson, you will learn how to:
- recognize an arithmetic sequence,
- find the common difference,
- write a sequence recursively,
- write a sequence explicitly,
- and find any term in the sequence.
1. What is an arithmetic sequence?
An arithmetic sequence is a sequence in which the difference between consecutive terms is always the same.
This fixed amount is called the common difference.
For example, in the sequence
\(4, 7, 10, 13, 16, \dots\)
each term increases by \(3\). So the common difference is \(d = 3\).
To check whether a sequence is arithmetic, subtract consecutive terms:
- \(7 - 4 = 3\)
- \(10 - 7 = 3\)
- \(13 - 10 = 3\)
Because the difference is always \(3\), this is an arithmetic sequence.
2. Arithmetic growth vs. other kinds of growth
Arithmetic sequences show additive growth. That means you add or subtract the same amount each time.
For example:
- Arithmetic: \(5, 8, 11, 14, 17\) — add \(3\) each time
- Not arithmetic: \(2, 4, 8, 16\) — multiply by \(2\) each time
The second pattern is exponential, not arithmetic, because it grows by multiplying, not by adding.
3. Important vocabulary
- Sequence: an ordered list of numbers
- Term: a number in the sequence
- First term: the starting number, often called \(a_1\)
- Common difference: the amount added or subtracted each time, called \(d\)
- Recursive formula: a rule that uses the term before it
- Explicit formula: a rule that gives any term directly
4. Recursive form
A recursive formula tells you how to get the next term from the previous term.
For an arithmetic sequence, the recursive form is:
$$a_n = a_{n-1} + d \quad \text{for } n \ge 2$$
You must also state the first term:
$$a_1 = \text{first term}$$
Example: For \(4, 7, 10, 13, \dots\)
the recursive rule is
$$a_1 = 4$$
$$a_n = a_{n-1} + 3$$
This means:
- start at \(4\),
- then keep adding \(3\).
5. Explicit form
An explicit formula lets you find any term without listing all the terms before it.
The explicit formula for an arithmetic sequence is:
$$a_n = a_1 + (n-1)d$$
Here:
- \(a_n\) is the \(n\)th term,
- \(a_1\) is the first term,
- \(d\) is the common difference,
- \(n\) is the term number.
This formula works because to get from the first term to the \(n\)th term, you add the common difference \((n-1)\) times.
6. Worked Example 1: Identify the common difference
Consider the sequence:
\(12, 17, 22, 27, 32, \dots\)
Step 1: Subtract consecutive terms.
- \(17 - 12 = 5\)
- \(22 - 17 = 5\)
- \(27 - 22 = 5\)
Step 2: Decide whether the difference stays constant.
Yes, the difference is always \(5\), so this is an arithmetic sequence.
Answer: The common difference is \(d = 5\).
7. Worked Example 2: Write recursive and explicit rules
Write both formulas for the sequence
\(3, 8, 13, 18, 23, \dots\)
Step 1: Find the first term and common difference.
- First term: \(a_1 = 3\)
- Common difference: \(8 - 3 = 5\), so \(d = 5\)
Recursive formula:
$$a_1 = 3$$
$$a_n = a_{n-1} + 5$$
Explicit formula:
Use $$a_n = a_1 + (n-1)d$$
Substitute \(a_1 = 3\) and \(d = 5\):
$$a_n = 3 + (n-1)(5)$$
Simplify:
$$a_n = 3 + 5n - 5$$
$$a_n = 5n - 2$$
Answer:
Recursive: $$a_1 = 3, \quad a_n = a_{n-1} + 5$$
Explicit: $$a_n = 3 + 5(n-1) \quad \text{or} \quad a_n = 5n - 2$$
8. Worked Example 3: Find a term far into the sequence
Find the \(20\)th term of the arithmetic sequence
\(7, 11, 15, 19, \dots\)
Step 1: Identify values.
- \(a_1 = 7\)
- \(d = 4\)
- \(n = 20\)
Step 2: Use the explicit formula.
$$a_n = a_1 + (n-1)d$$
$$a_{20} = 7 + (20-1)(4)$$
$$a_{20} = 7 + 19 \cdot 4$$
$$a_{20} = 7 + 76$$
$$a_{20} = 83$$
Answer: The \(20\)th term is \(83\).
This shows why the explicit formula is useful. It helps you jump straight to the term you want.
9. Worked Example 4: Arithmetic sequence with a negative difference
Consider the sequence
\(30, 24, 18, 12, 6, \dots\)
Step 1: Find the common difference.
- \(24 - 30 = -6\)
- \(18 - 24 = -6\)
So \(d = -6\).
Step 2: Write the explicit formula.
Here, \(a_1 = 30\) and \(d = -6\).
$$a_n = a_1 + (n-1)d$$
$$a_n = 30 + (n-1)(-6)$$
$$a_n = 30 - 6(n-1)$$
You could also simplify:
$$a_n = 30 - 6n + 6$$
$$a_n = 36 - 6n$$
Step 3: Find the 6th term.
$$a_6 = 30 + (6-1)(-6)$$
$$a_6 = 30 + 5(-6)$$
$$a_6 = 30 - 30$$
$$a_6 = 0$$
Answer: The explicit formula is $$a_n = 30 - 6(n-1)$$ and the 6th term is \(0\).
10. How to write an arithmetic sequence from a situation
Arithmetic sequences often come from real-life patterns.
Example: A student has \(\$10\) in savings and adds \(\$4\) every week.
The amount of money after each week forms an arithmetic sequence:
\(10, 14, 18, 22, 26, \dots\)
Here:
- first term: \(a_1 = 10\)
- common difference: \(d = 4\)
The recursive formula is
$$a_1 = 10$$
$$a_n = a_{n-1} + 4$$
The explicit formula is
$$a_n = 10 + (n-1)4$$
$$a_n = 10 + 4(n-1)$$
This means the savings grow by the same amount each week, so the pattern is arithmetic.
11. Common mistakes to avoid
- Mixing up adding and multiplying: If the pattern multiplies, it is not arithmetic.
- Forgetting \((n-1)\): The explicit formula is $$a_n = a_1 + (n-1)d$$ not just \(a_1 + nd\).
- Using the wrong common difference: Always subtract consecutive terms carefully.
- Not stating the first term in recursive form: A recursive rule needs a starting point.
12. Quick check for understanding
- Is \(2, 6, 10, 14, \dots\) arithmetic? What is the common difference?
- Write a recursive rule for \(9, 12, 15, 18, \dots\).
- Write an explicit formula for \(5, 9, 13, 17, \dots\).
- Find the 15th term of \(1, 4, 7, 10, \dots\).
Answers:
- Yes. The common difference is \(4\).
- $$a_1 = 9, \quad a_n = a_{n-1} + 3$$
- $$a_n = 5 + (n-1)4$$
- $$a_{15} = 1 + (15-1)3 = 1 + 42 = 43$$
13. Summary
An arithmetic sequence is a number pattern with the same common difference between consecutive terms.
You can describe it recursively by telling how to get the next term from the previous one:
$$a_1 = \text{first term}, \quad a_n = a_{n-1} + d$$
You can also describe it explicitly with a formula for any term:
$$a_n = a_1 + (n-1)d$$
If the sequence changes by adding or subtracting the same amount each time, it is arithmetic. Recognizing this pattern helps you model linear growth in math and in real-life situations.
Put what you read to the test
You've worked through Arithmetic Sequences. Try answering a few questions to see what stuck — and what might deserve a quick reread before you move on.